Question

If 0.15g of the Solute dissolved in 159
of solvent, increases the boiling point
by 0.2166 over to that of purse solvent
the molecular mass of substance is
(Kb = 2.16k kg mol's​

Answer 1

Answer:

100

We know,

ΔT

b

=

M×W

K

b

×w×1000

⇒M=

ΔT

b

×W

K

b

×w×1000

=

0.216×15

2.16×0.15×1000

=100.