If 0.179 K2CO3, potassium carbonate, is dissolved in 450 mL of solution, what is the molarity
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In the part of the 179 moles K2CO3 the respective potassium carbonate get dissolves in the 450 ml of the given solution and you end to calculate the morality solution at the stage of the 95.5 g.
Then you need to convert the volume in the cm3 to L and 1 cm3 = 1 ML =1.10-3 L is answer.
Therefore the student can simply get best ideas of reading it.
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