Question

If 0.2 molal aqueous solution of a weak acid (HA) is 40% ionised then the freezing point of the solution will be (Kf for water = 1.86°C/m)

Answer 1

Answer:

If 0.2 molal aqueous solution of a weak acid (HA) is 40% ionised then the freezing point of the solution will be (Kf for water = 1.86°C/m)  – 0.52°C

Explanation:

: ΔTf = iKfm and i = (1 – α + nα)

Sol. : i = (1 – 0.4 + 2 × 0.4) = 1.4

ΔTf = 1.4 × 1.86 × 0.2

= 0.52

0 – Tf = 0.52

Tf = – 0.52°C

Answer 2

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