Question

if 0.2 ohm is the resisitance per unit length of the wire then the resistance of meter bridge is​

Answer 1

Explanation:

Resistance of meter bridge =100×0.1=10Ω

6

x

=

3

2

→x=4Ω

R

t

1

=

6+4

1

+

10

1

→R

T

=5

I=

R

T

V

=

5

5

=1A

mark as Brainliest

Answer 2

Explanation:

R=s(l+0.2)/(100-l)+0.2......... is resistance