If (0.2)x = 2 and log 2 = 0.3010, then the value of x to the nearest tenth is:
(a) -10.0, (b) -0.5, (c) -0.4, (d) -0.2, (e) 10.0
Answers
Answered by
2
Answer:
c option is correct
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Explanation:
0.2)
x
=2⟹x=log
0.2
2=
log
2
0.2
1
=
1−log
2
10
1
=
1−
0.3010
1
1
[∵log2=0.3010]
∴x=−0.4
Answered by
3
(0.2) x = 2
taking log on both sides
∴log(0.2)x = log (2)
⇛xlog (0.2) = 0.3010
⇛x log
= 0.3010
x [log 2 - log 10] = 0.3010.
x [log 2 - 1] = 0.3010,[since log 10=1].
x [0.3010 -1] = 0.3010, [since log 2 = 0.3010].
x[-0.699] = 0.3010.
x = 0.3010/-0.699.
x = -0.4306….
x = -0.4 (nearest tenth)
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