Question

 If (0.2)x = 2 and log 2 = 0.3010, then the value of x to the nearest tenth is:

(a) -10.0,
(b) -0.5,
(c) -0.4,
(d) -0.2,
(e) 10.0​

Answer 1

Given

$(0.2)x = 2 \\ \\ = > x = \frac{2}{0.2} \\ \\ = > x = \frac{2 \times 10}{2} \\ \\ = > x = 10.0$

Thus your answer is = e) 10.0

Answer 2

Answer:

Step-by-step explanation:

Solution:

(0.2)x = 2.

Taking log on both sides

log (0.2)x = log 2.

x log (0.2) = 0.3010, [since log 2 = 0.3010].

x log (2/10) = 0.3010.

x [log 2 - log 10] = 0.3010.

x [log 2 - 1] = 0.3010,[since log 10=1].

x [0.3010 -1] = 0.3010, [since log 2 = 0.3010].

x[-0.699] = 0.3010.

x = 0.3010/-0.699.

x = -0.4306….

x = -0.4 (nearest tenth)

Answer: (c)