Question

If 0.2M, 100ml Hcl solution is mixed
with 0.1M, 300 ml Hcl solution . Find
molarity of mixture​

Answer 1

Explanation: molarity of mixture

given that:

M1=0.2

M2=0.1

V1=100ml

V2=300ml

molarity of mixture=M1×V1 +M2×V2/V2+VI

0.2x100+0.1x300/400

0.5/4

I/8

I.25

Answer 2

Answer:

0.125M

Explanation:

Given,

        M1 =0.2M    ,V1 = 100ml         &

        M2 =0.1M    ,V2 = 300ml

We know that

   M1V1 +M2V2 = MV3

                   where M is the molarity of the mixture and V3 is the volume of the mixture

Therefore,

    0.2*100 + 0.1*300 = M*(100+300)

implies,

      20 + 30 =M*400

⇒ M = 0.125M

        Molarity of mixture is 0.125M

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