If 0 = 30°, verify that
(1) sin 20 = 2 sin cos ook
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Q = 30°
Sin 2Q = 2sinQ cosQ
LHS = Sin (2×30 )
= Sin 60
= √3 / 2
RHS = 2SinQ CosQ
= 2 Sin (30) Cos (30 )
= 2 × (1/2) × ( √3 /2 )
= √3 / 2
LHS = RHS
hence proved
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