If (0, 4) and (0, 2) are respectively the vertex and focus of a parabola. Then find its
equation.
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Answer:
Step-by-step explanation:
Answer : x2+8y−32=0
The coordinates of the vertex is (0,4)
The coordinates of the focus is (0,2)
It is clear that the vertex and the focus lies on the positive side of the y-axis.
Hence the curve is open downwards.
The equation of the form (x−h)2=4a(y−k)
(ie) (x−0)2=−4×2(y−4)
On simplifying we get,
x2=−8(y−4)
⇒x2=−8y+32
x2+8y−32 is the required equation of the parabola. Reply please
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