Chemistry, asked by soumyadarshi, 5 hours ago

if 0.4g of NAOH is present in 40ml of solution what is the molarity and normality of solution​

Answers

Answered by shrirampawar249
0

molarity = no \: of \: moles \:  \div volume(in \: l) \\ m =  \frac{n}{v}  \\ m =  \frac{given \: mass}{molecuar \: mass}  \times  \frac{1000}{v(in \: l)}  \\ m =  \frac{0.4}{23  +  16 + 1}  \times  \frac{1000}{40}  \\ m =  \frac{0.4}{40}  \times  \frac{100}{4}  \\ m =  \frac{4}{400}  \times  \frac{100}{4}  \\ m =  \frac{4}{4}  \times  \frac{1}{4}  \\ m =  \frac{1}{4}  = 0.25m \\

equivalent \: mass \: of \: naoh =  \frac{atomic \: weight}{valency}  \\  =  \frac{23}{1}  = 23 \\ normality =  \frac{equivalent \: weight}{molecuar \: weight}  \times  \frac{1000}{v(in \:  \: l) }  \\  =  \frac{23}{40}  \times  \frac{1000}{40}  \\  =  \frac{23 \times 10}{16}  \\  =  \frac{230}{16}  \\  = 14.3n

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