Chemistry, asked by avtarsandhawali, 1 year ago

If 0.5 g of a mixture of two metals A and B with respective equivalent weights 12 and 9 displace 560 ml of H2 at STP from an acid , the composition of the mixture is

Answers

Answered by danielochich
6
Molar gas volume at STP = 22400 mL

Moles of H2 = 560/22400

                    = 0.025

Mass of H2 = 0.025 x 2  = 0.05g

Let mass of metal A = x

Mass of metal B = 0.5  - x



x/12 + (0.5 - x) /9 = 0.05

Giving:

x = 0.2 (see the attached solution)

0.5 - x = 0.5 - 0.2 = 0.3


Mass of metal A = 0.2g

Mass of metal B = 0.3g

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