Question

If 0.5 mol of BaCl2 is mixed with 0.2 mol of Na3PO4 th maximum number of mole of Ba3(PO4)2 that can be formed is??

Answer 1

Hey dear here is your answer

The answer is (d) 0.10 mole.

The equation for this precipitation (double decomposition) reaction is:

                         3 BaCl2 + 2 Na3PO4 = Ba3(PO4)2 + 6 NaCl

Stoichiometrically, 2 moles of Na3PO4 can react with 3 moles of BaCl2 to form 1 mole of Ba3(PO4)2.
Therefore, 0.2 mole of Na3PO4 can only react with 0.3 mole of BaCl2 to form 0.1 mole of Ba3(PO4)2. 
(And, o.2 mole of BaCl2 will remain unreacted.

Please mark me as brainliest,Thank you and follow me.