Question

If 0.5 mol of BaCl₂ is mixed with 0.2 mole of Na₃PO₄, find the maximum amount of Ba₃(PO₄)₂ that can be formed.
(a) 1 mole
(b) 0.5 mole
(c) 0.1 mole
(d) 0.01 mole

Answer 1

Answer:

3BaCl

2

+2Na

3

PO

4

→Ba

3

(PO

4

)

2

+6NaCl

The coefficients of the balanced equation tell you the ratio of the reactants and the products.

3 moles of BaCl

2

react with 2 moles of Na

3

PO

4

to yield 1 mole of Ba

3

(PO

4

)

2

.

Required ratio of BaCl

2

:Na

3

PO

4

=3:2.

0.5 mole BaCl

2

requires 2/3 x 0.5 mole (0.333 mole) Na

3

PO

4

.

You have only 0.2 mole Na

3

PO

4

so it is limiting and BaCl

2

is in excess.

2 moles of Na

3

PO

4

will yield 1 mole of Ba

3

(PO

4

)

2

.

0.2 mole Na

3

PO

4

will yield 0.1 mol of Ba

3

(PO

4

)

2

.

D: 0.1 mol yield.