If 0.5 mol of BaCl₂ is mixed with 0.2 mole of Na₃PO₄, find the maximum amount of Ba₃(PO₄)₂ that can be formed.
(a) 1 mole
(b) 0.5 mole
(c) 0.1 mole
(d) 0.01 mole
Answers
Answered by
2
Answer:
3BaCl
2
+2Na
3
PO
4
→Ba
3
(PO
4
)
2
+6NaCl
The coefficients of the balanced equation tell you the ratio of the reactants and the products.
3 moles of BaCl
2
react with 2 moles of Na
3
PO
4
to yield 1 mole of Ba
3
(PO
4
)
2
.
Required ratio of BaCl
2
:Na
3
PO
4
=3:2.
0.5 mole BaCl
2
requires 2/3 x 0.5 mole (0.333 mole) Na
3
PO
4
.
You have only 0.2 mole Na
3
PO
4
so it is limiting and BaCl
2
is in excess.
2 moles of Na
3
PO
4
will yield 1 mole of Ba
3
(PO
4
)
2
.
0.2 mole Na
3
PO
4
will yield 0.1 mol of Ba
3
(PO
4
)
2
.
D: 0.1 mol yield.
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