Question

[If 0.5A current is flowing through a 50 Ohm resistor for 3 minutes
a) Calculate the heat released. b) Calculate the power
. a) 2230j, b) 15w
. a) 2450j, b) 13w
. a) 2250j, b) 12.5w
. a) 2650j, b) 12w​

Answer 1

Explanation:

Heat released

$= {i}^{2} r \\ = 0.5 \times 0.5 \times 50 \\ = 12.5 \:$

Power emitted

$= {i}^{2} rt \\ = {0.5}^{2} \times 50 \times 3 \times 60 \\ = 2250 \:$