Question

If (0,6), (-4,0) and ( 5,0) are the vertices of a triangle then, its area is​

Answer 1

Answer:

Let the vertices of the triangle be A (5,0), B (-7,0) and C (6,4).

Distance AB = {(5+7)^2 + 0}^0.5 = 12 units

Distance BC = (13^2+4^2)^0.5 = 13.60147051 units

Distance CA = [(6–5)^2 + (4–0)^2]^0.5 = [1+16}^0.5 = 4.123105626 units.

2s = AB + BC + CA = 12 + 13.60147051 + 4.123105626 = 29.72457613, so

s = 29.72457613/2 = 14.86228807

By Heron’s formula, Area of ABC = [14.86228807 x (14.86228807–12) x (14.86228807-13.60147051) x (14.86228807-4.123105626)]^0.5

= [14.86228807 x 2.86228807 x 1.260817557 x 10.73918244]^0.5

= 24 sq units.

The area of the triangle ABC = 24 sq units.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

area of the triange is equal to

1/2[ x1(y2-y3)+ x2(y3-y1) + x3(y1-y2) ]

here

x1 = 0

x2=-4

x3=5

y1=6

y2=0

y3=0

always remember that the area cant be negative so always take the answer possitive(if you get a negative answer also). do the rest by giving the values in those places do the answer thats it.

MARK BRAINLIEST.