Question

if 0.600 mole of chlorine gas is reacted with 0.500 mole of aluminium to produce aluminium chloride which reactant is an excess?? how many moles of aluminium chloride can be produced during the reaction?? ​

Answer 1

Answer:

This is actually a Balanced chemical equation.

2Al(s) + 3Cl2(g)-------> 2AlCl3 (s)

From the above equation, it can be seen that 2 moles of Al combine with 3 moles of Cl and produce 2 moles of AlCl3.

2 mole of Al=2 mole of AlCl3

3 mole of Cl= 2 mole of AlCl3

Now, according to your question, 0.600 mole of Cl and 0.500 mole of Al has been given.

2 mole of Al= 2 mole of AlCl3

0.500 of Al= x

As we see, mole of Al and AlCl3 are same, so 0.500 mole of Al produce 0.500 mole of AlCl3.

Now for Cl

3 mole of Cl= 2 mole of AlCl3

0.600 mole of Cl=x

By cross multiplication;

2×0.600/3= 0.4

As, Al produces 0.500 mole of AlCl3 and Cl produces 0.4 mole of AlCl3, it is concluded that Al is in excess and Cl is a limiting reagent. As limiting reagent stops the reaction, so the number of moles of AlCl3 produced is;

3 mole of Cl= 2 mole of AlCl3

0.600 mole of Cl=x

2×0.600/3= 0.4 mole