Question

if 0.75g of an organic compound in Kjeldahl 's method neutralized 30ml of 0.25N H2SO4 the percentage of nitrogen in the compound is a)28 b)50 c) 14
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Answer 1

Answer:

37.33

Explanation:

10 ml of 1MH

2

SO

4

corresponds to 10 mmol.

It will neutralize 20 mmol of NH

3

.

Weight of N=

1000

14×20

g=0.280g.

Thus 0.75 g of sample of organic compound contains 0.280 g of nitrogen.

The percentage of nitrogen in the organic sample is

0.75

0.280

×100=37.33