Question

If 0.8 mole of electrons flow through a wire in 55 minutes. What is (a) the total charge in kilocoulomb that passes through the wire and (b) the magnitude of the current? Avogadro's number =6xx10^(23) per mole.

Answer 1

Explanation:

plz find the answer in attachment

Answer 2

Answer:

a) 7.70*10⁴ kilocoulomb

b) 2.33×10⁴ A

Explanation:

Number of electrons in 0.8 moles of electrons=0.8*Avogadro's number

=$0.8*6.02*10^{23} =4.816*10^{23}\ electrons.$

Part A:

Charge on each electron=$1.6*10^{-16} C$

So charge on 0.8 mole electron

=$=4.816*10^{23}* 1.6*10^{-16} C\\7.70*10^{7} C$

=7.70*10⁴ kilocoulomb

Hence, 7.70×10⁴ kilocoulomb is the charge flown through the wire.

Part B:

Current is the charge flown through the wire,

$i=\frac{Q}{t}$

as the time given is 55 minutes which on converting to seconds,

t=55×60=3300seconds.

$i=\frac{7.70*10^{7} }{3300} =2.33*10^{4} A$

Hence, 2.33×10⁴ A is the current flown through the wire.