Question

If 0.950 mol of O2 has a volume of 20.0 L at some temperature and pressure, what would be the volume of 1.350 mol of O2?

Answer 1

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Answer 2

According to the question;

0.950 mole of Oxygen has a volume of 20.0L keeping the temperature and pressure constant.

As we know,

If nothing is mentioned about the nature of the gas then we can consider the gas as ideal gas.

So, Ideal gas equation is :-

    P v = n R T

where, P = Pressure

            v = volume

            n = number of moles

            R= universal gas constant

            T= temperature

According to the question, Pressure and temperature are constant.

So,

    V ∝ n

we can write this equation as;

$\frac{V1}{V2} = \frac{n1}{n2}$

Let us assume that,

n1 = 0.950 mol

n2=  1.350 mol

V1 = 20.0 L

V2 = ?

Putting all these values in the equation,

$\frac{20}{V2} = \frac{0.950}{1.350}$

V2 = 28.42 L

Hence, the volume occupied by 1.350 mol will be 28.42 L.