Question

If (0, a) and (b, 0) are the solutions of the linear equation 3x = 7y - 21. Find a and b.​

Answer 1

3(0)=7(a)-21

21=7(a)

a=3

3(b)=7(0)-21

3(b)=0-21

b=-7

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Answer 2

Answer:

Required value of a is 3 and value of b is (-7)

Step-by-step explanation:

Given equation is

$3x = 7y - 21.....(1)$

It is also given that (0,a) and (b,0) are the solution of the given equation.

Here we want to find value of a and b.

By Value putting method,we can solve this problem.

Now question is how can we use value putting method ?

By one example,we can understand this concept more easily.

We are taking an equation $5x + y + c = 0$

and let (1,2) be solution of the equation.

So,

$5 \times 1 + 2 + c = 0 \\ 5 + 2 + c = 0 \\7 + c = 0 \\ c = - 7$

Here we are putting (0,a) in equation (1) and get

$3 \times 0 = 7 \times a - 21 \\ 7a - 21 = 0 \\ 7a = 21 \\ a = \frac{21}{7} \\ a = 3$

again we are putting (b,0) in equation (1) and get,

$3 \times b = 7 \times 0 - 21 \\ 3b = - 21 \\ b = \frac{ - 21}{3} \\ b = - 7$

So, required value of a is 3 and value of b is (-7).

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