if 0 and 1 are the zero of the polynomial l (x) = 2x^3_3x^2+ax+ b
dheerajnaidu808:
what to prove
Answers
Answered by
0
we know sum of zeroes in cubic poly is -b/a
so 0+1+x = 3/2
so x = 3/2 -1
so x =1/2
so 0+1+x = 3/2
so x = 3/2 -1
so x =1/2
Answered by
2
p(x)=2x^3-3x^2+ax+ b
p(0)=2×(0)^3-3×(0)^2+a×0+b
=2×0-3×0+0+b
=0-0+b
b=0. .........(i)
p(1)=2×(1)^3-3×(1)^2+a×1+b
=2×1-3×1+a+b
=2-3+a+b
=-1+a+b
a+b=1
b=1-a..........(ii)
from(i) & (ii),
0=1-a
a=1
Answer:-
a=1
b=0
p(0)=2×(0)^3-3×(0)^2+a×0+b
=2×0-3×0+0+b
=0-0+b
b=0. .........(i)
p(1)=2×(1)^3-3×(1)^2+a×1+b
=2×1-3×1+a+b
=2-3+a+b
=-1+a+b
a+b=1
b=1-a..........(ii)
from(i) & (ii),
0=1-a
a=1
Answer:-
a=1
b=0
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