If 0 and 1are the zero es of the polynomial f (X)=2x3-3x2+ax+b, find the value of a and b
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Answer:
f(x)=2x³-3x²+ax+b
f(0)=2(0)³-3(0)²+a(0)+b=0
⇒b=0
f(1)= 2(1)³-3(1)²+a(1)+b=0
=2-3+a+b=0
=a+b=1
=a=1
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