If √ = ° < ≤ °; : [3] √ + −
Answers
Answer:
Answer
Given sin(A+B)=1
⇒sin(A+B)=sin90
o
(∵sin90
o =1)⇒A+B=90 o …………(1)
Again, cos(A−B)= 3 /2⇒cos(A−B)=cos30 o (∵cos30 o = 3 /2)⇒A−B=30 o………(2)
Adding (1)+(2)
A+B+A−B=90
o +30 o⇒2A=120 o⇒A=120/2
⇒A=60 oPutting A=60 o in equation-(2) we getA−B=30 o⇒60o −B=30o⇒60o −30o=B⇒B=30 o∴A=60 o ;B=30 o .
Answer:
find a cubic root (or generally root of degree
find a cubic root (or generally root of degree n
find a cubic root (or generally root of degree n ) you have to use de'Moivre's formula:
From tis formula you can see, that every complex number has
From tis formula you can see, that every complex number has n
From tis formula you can see, that every complex number has n roots of degree
From tis formula you can see, that every complex number has n roots of degree n
From tis formula you can see, that every complex number has n roots of degree n
From tis formula you can see, that every complex number has n roots of degree n So to calculate root of a complex number you first have to write the number in a trigonometric form