Question

If
0 <a, ß <
tan 2a
cos (a +B) =
49​

Answer 1

Step-by-step explanation:

Given tan(α+β)=3,tan(α−β)=2

tan2α=tan((α+β)+(α−β))=

1+tan(α+β)tan(α−β)

tan(α+β)+tan(α−β)

=

1−(3)(2)

3+2

=−1

As 0≤α≤90

∘

⟹0≤2α≤180

∘

⟹2α=135

∘

sin2α=sin135

∘

=

2

1