Question

if 0<α<90 and 2sinα=√3 cos10+sin10 then α =

Answer 1

Divide your equation with 2. You get sinA=(√3/2)cos10 + (1/2)sin10. Now, √3/2=sin60 and 1/2=cos60. This is sinA=sin60*cos10+cos60*sin10. Hence, sinA=sin70 and A=70 as A lies between 0 and 90