Math, asked by rmdolic11, 1 month ago

if 0<X<300 and [x/2] + [x/5] +[x/10] = 4x/5 sum of all possible values of x is m than [ m/100]=​

Answers

Answered by yadavsatyapal059
2

x=[x]+{x}

[x]=x-{x}

[x2]+[x3]+[x5]=31x30

x2−{x2}+x3−{x3}+x5−{x5}=31x30

x2+x3+x5−[(x2)+(x3)+(x5)]=31x30

3x30=t

t=0

x is multiple of 2,3,5

LCM of(2,3,5)=30

x=30m

0<30m<1000

n=1to33

33 possibles values of x.

Answered by nihasrajgone2005
1

Answer:

x=[x]+{x}

[x]=x-{x}

[x2]+[x3]+[x5]=31x30

x2-{X2}+x3-[x3]+x5-{x5)=31x30

x2+x3+x5-[(x2)+(x3)+(x5)]=31x30

3x30=t

t=0

x is multiple of 2,3,5

LCM of(2,3,5)=30

x=30m

0<30m<1000

n=1to33

33 possibles values of x.

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