Question

if 0 < x <=pie /2 , then minimum value of sinx+ cosecx​

Answer 1

Answer:

$AM\geq GM\\\frac{(sinx+\frac{1}{sinx})}{2} \geq \sqrt{\frac{sinx}{sinx}}\\ sinx+\frac{1}{sinx}\geq  2\\so minimum value is 2.$

Step-by-step explanation: