Question

If 0° < A and B < 90° such that cos A = 5/13 and sin B =4/5 ,then find sin (A+B)

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Answer 1

Answer:

I don't know what is the answer but I will tell after 2 years so wait for 2 years

Answer 2

Step-by-step explanation:

cosA=5/13

as we know 5,12,13 is a triplet

hence,

sinA=12/13

as√1-cos²A=sinA

sinB=4/5

as we know 3,4,5 is triplet

√1-sin²B=cosB

hence,cosB=3/5

we know,

sin(A+B)=sinAcosB+cosAsinB

=12/13×3/5+5/13×4/5

=36/65+20/65

=(36+20)/65

=56/65