Question

If 0° < theta < 25°, prove that cos (65° + theta) - sin (25° - theta) = 0.​

Answer 1

Answer:

hope you understand..

Step-by-step explanation:

Answer

tan(65−θ)⇒tan[90−(65−θ)]

⇒cot(25+θ)

put in equation

cot(25+θ)−cot(25+θ)=0

Answer 2

Answer:

0° < theta < 25°, prove that cos (65° + theta) - sin (25° - theta) = 0. then angle 25 and if cos 65 plus theta is equal to or less then or greater than equal to. then it must be sin 25 degree minus theeta

so

sin 25 minus theta equal to zero