If 02 - 32 + 2) (12 – 7u + 1 2)x3 +
(22 – 42 + 3) (u2 – 6u +8)x2 + 5x +7
is a linear polynomial in x, then value 2 + u can
be
(1) 1
(2) 2
(3) 3
(4) 5
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Answer:
If 02 - 32 + 2) (12 – 7u + 1 2)x3 +
(22 – 42 + 3) (u2 – 6u +8)x2 + 5x +7
is a linear polynomial in x, then value 2 + u can
be
(1) 1
(2) 2
(3) 3
(4) 5
Answered by
8
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