if .0409 g of hydrogengas was present in 500 cm (cube) of a flask at 300kand 760 mm of hg. find molar mass of hydrogen?
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P V = n RT
(13.6 * 1000 * 0.760 * 9.81 ) Pa * (500 * 10^-6 m³) = n * 8.31 J/mole/⁰K * 300 ⁰K
n = 0.020336 moles of hydrogen
molar mass = 0.0409 gms / 0.020336 moles = 2.0111 gms/mol
=> molar mass = 2 gms/ mole
(13.6 * 1000 * 0.760 * 9.81 ) Pa * (500 * 10^-6 m³) = n * 8.31 J/mole/⁰K * 300 ⁰K
n = 0.020336 moles of hydrogen
molar mass = 0.0409 gms / 0.020336 moles = 2.0111 gms/mol
=> molar mass = 2 gms/ mole
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