If 0and 1are the zeroes of the polynomial f(x)=2x³-3x²+ax+b find the value of a and b
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f(0)=0-0+0+b=b=0
f(1)=2-3+a+b=a+b-1=0
a+0-1=0
a=1
hence a=1 and b=0
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