Math, asked by Kavneet6116, 21 hours ago

If 1(0!)+3.(1!)+7(2!)+13(3!)+21(4!)+⋯ n terms = (4000)(4000!) Then what is the value of n.

Answers

Answered by khushibishnoi35

0

Answer:

eg bhurej2feejubkjguubrjbgerjjchhrrjb

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