Question

If 1 + 10 square a upon 1 + cot square a is equal to

Answer 1

Answer:

$\huge \green{ \boxed{ \pink{\boxed{ \red { \mathfrak{solution}} }}}} \\ \\ we \: have \: \\ \\ \implies \: \frac{1 + {tan}^{2}a }{1 + {cot}^{2}a } \\ \\ \red{ \implies} \green{ \frac{1 + {tan}^{2}a}{1 + \frac{1}{ {tan}^{2}a } }} \\ \\ \implies \red{ \frac{1 + {tan}^{2} a}{ \frac{1 + {tan}^{2}a }{ {tan}^{2} a} } } \\ \\ \implies \orange{ {tan}^{2} a} \: \\ \\ \\ that \: is \: your \: answer$

Answer 2

The value of  $\left ( \frac{1+\tan^2A}{1+\cot^2A} \right ) = \tan^2A$

Step-by-step explanation:

given :

$\left ( \frac{1+\tan^2A}{1+\cot^2A} \right )$

using the identity

$1+\tan^2A = \sec^2A\\\\\cot^2A +1 =\csc^2A$

therefore ,

$\left ( \frac{1+\tan^2A}{1+\cot^2A} \right ) = \frac{\sec^2A}{\csc^2A}\\\\\frac{1}{\cos^2A}\times \frac{\sin^2A}{1}= \tan^2A$

Hence , The value of  $\left ( \frac{1+\tan^2A}{1+\cot^2A} \right ) = \tan^2A$

#Learn more:

https://brainly.in/question/8381420