Question

if (1÷16)^4-3x×8^x-2=(0.25)^x then find the value of 17 x÷22+1

Answer 1

{1÷16}^4-3x × 8^x-2 = {0.25}^x⇒{2}^-4{4-3x} × 2^3{x-2} = 2^{-2}x

{2}^{-16+12x} × 2^{3x-6}= 2^-2x⇒2^{-16+12x} + {3x-6} = 2^-2x

2^{15x-22}  = 2^-2x⇒15x-22=-2x⇒{15+2}x = 22

17x=22⇒x=22/17

⇒17x÷22+1 ⇒[17{22/17}]/22 +1⇒22/22 +1

⇒1+1=2