Question

if 1+1bya =1 then find a cube +1​

Answer 1

$\huge\bigstar\sf\red{Answer:}$

$\sf{1+\dfrac{1}{a}=1=1}$

$\sf{\therefore{\dfrac{1}{a}=0}}$

$\sf{\therefore{a=0}}$

$\sf{(a^{3}+1)=0+1}$

$\sf{=1}$

$\sf{The \ value \ of \ a^{3}+1=1.}$