Math, asked by CloudyMan566, 6 months ago

If 1^2 + 2^2 + 3^2 + ..... 19^2 = 2470, then the
value of (2^2 4^2 +6^2 ... +38^2) is:

Answers

Answered by shreya2320

1

Answer:

1+4+9+....+361=2470

Step-by-step explanation:

375+....=2470

= 2095 Ans

Previous Question

Next Question

Similar questions

Math, 3 months ago

2/5n +7= 12. solve for n...

Math, 3 months ago

3. Multiply (Find the product): (1) (x + 2) x (y + 3)...

Accountancy, 3 months ago

Sneha invested Rs.75,000 in equity shares of Rs. 10 F.V. and market value of Rs. 85 each After receiving 15% dividend she sold all the shares at Rs.70 each. She paid brokerage of 1.5% on both the transaction. Find her profit or loss.

Economy, 6 months ago

solve this question...

Math, 6 months ago

56 - 36 ÷ 4 × 2 + 7 in full process...

English, 10 months ago

She gives me gift of flowera change the vioce...

Science, 10 months ago

5) If a fish had a round body, would it be able to swim in water easily? Give reasons for your answer.

English, 10 months ago

I too was able to clap sincerely (remove too)...