Math, asked by CloudyMan566, 6 months ago

If 1^2 + 2^2 + 3^2 + ..... 19^2 = 2470, then the
value of (2^2 4^2 +6^2 ... +38^2) is:

Answers

Answered by shreya2320

1

Answer:

1+4+9+....+361=2470

Step-by-step explanation:

375+....=2470

= 2095 Ans

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