Question

if 1/2,3/2,5/2,7/2,9/2..........then find the nth term of arithmetic progression​

Answer 1

Answer:

Formula Used.

dn = an + 1 – an

an = a + (n–1)d

In the above sequence,

a =

;

d1 = a2–a1 =

= 1

d2 = a3–a2 =

= 1

d3 = a4–a3 =

= 1

The difference in sequence is same and comes to be (1).

∴ The above sequence is A.P

The nth term of A.P is an = a + (n–1)d

an = a + (n–1)d =

+ (n–1)(1)

=

+ n–1

= n–

Answer 2

Answer:

Arithmetic Progession

an = a+ (n-1)d

Here a = 1/2

d¹ = a2 -a1 = 3/2 - 1/2 = 1

d2 = a3 -a2 = 5/2 - 3/2 = 1

d3 = a4 - a3 = 9/2 - 5/2 = 1

So , here is clear that difference is common ( 1 )

Let's find n th term

an = a + (n - 1 ) d

an =1/2 + ( n - 1 ) ( 1 )

= 1/2 + n - 1

Here LCM is 2

- n = 1 / 2 - 1 x 2 / 1 x 2

= 1 / 2 - 2 / 2

-n = 1 / 2

The n th term is never in negetive

so we take the negative sign on other side

Thus , n = - 1 / 2

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