Question

If 1+2+3+....+6= 6(6+1) 2 ; then 1³+2³+3³+ ____+6³=​

Answer 1

Answer:

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Answer 2

Answer:

Formula for 1^3 + 2^3 + 3^3 + ……….. + n^3 is given as:

[n(n+1)/2]^2

So, 1^3 + 2^3 + 3^3 + 4^3 + 5^3 + 6^3 + 7^3

= [7*(7+1)/2]^2

= [7*8/2]^2

= 28^2

= 784