Math, asked by gopalapandi1212, 2 days ago

If (1,-2),(3,6),(x,10) and (3,2) are the vertices of the parallelogram taken in order then the value of x is

Answers

Answered by aajaxkhan4722
0

Answer:

let,

( 1,-2), ( 3,6), (x, 10) and ( 3, 2)

are the verticles of A, B, C, D Intersection of point O are the mid - point of AC = ( 1 + x / 2 , -2 + 10 / 2)

= (1 + x /2 , 4 ) equation 1st

step-by-step:

co-ordinates of point O are mid- point of BD.

= ( 3+3 /2 , 6+2 /2 )

= ( 3, 4 ) equation 2nd

from 1st and 2nd equation both co-ordinates of point O

1+x/ 2 = 3

1+x= 6

x= 6 - 1

x= 5

Hence, the value of x = 5 (Answer)

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Answered by s15084cvanteedu13064
2

the value of X is

( 1 ). 6

( 2 ). 5

( 3 ) 4

( 4 ). 3

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