Question

if 1, 2, 3 and so on are in AP then the sum of the first 120 terms is​

Answer 1

Answer:

Step-by-step explanation:

a=1 , d=1 , Sn=n/2(2a+(n-1)d). =120/2(2(1)+(120-1)1). =60(2+119). =60(121). =7260