if 1+2+3+......+k=325,find 1 ^3+2^3+3^3+.......k^3
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Answer:
105625
Step-by-step explanation:
so from given 1st series we will find k
as we know sum of series is n(n+1)/2
we have to find n as sum is 325
so n(n+1)/2=325
we have n=25
then we have k=25
we can now use the formula for cubic sum of series i.e. {n(n+1)/2}^2
={25x26/2}^2
105625 will be the answer
OR
simply square the sum of normal series to find the sum of cubic series
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