if (1,2), (4,y)(x,6) and (3,5) are the vertices of a parallelogram taken in order find x and y
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diagonals of parallelogram bisect each other
let ABCD be that parallelogram where A(1,2),B(4,y),C(x,6),D(3,5)
find the mid point of AC. it will come as O((1+x)/2,4).......(1)
similarly, for BD it wil come O(7/2,(y+5)/2).........(2)
equate (1) and (2)......
u will get 7/2=(1+x)/2
therefore x=6
and
(y+5)/2=4
therefore y=3.
thts ur ans!!!!! :)
let ABCD be that parallelogram where A(1,2),B(4,y),C(x,6),D(3,5)
find the mid point of AC. it will come as O((1+x)/2,4).......(1)
similarly, for BD it wil come O(7/2,(y+5)/2).........(2)
equate (1) and (2)......
u will get 7/2=(1+x)/2
therefore x=6
and
(y+5)/2=4
therefore y=3.
thts ur ans!!!!! :)
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