If (1,2),(4,y) ,(x,6) and(3,5) are the vertices of parallelogram then in order, then find x and y
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(1,2),(4,y),(x,6) and (3,5) are vertices of triangle
ABCD is parallelogram
AC and BD will bisect each other.Hence , midpoint of AC and midpoint of BD are same point
BY MIDPOINT FORMULA,
Midpoint formula of Ac and BD
1+x/2 =4+3/2 and 2+6/2 =5+y/2
1+x =7 and 8=5+y
x=6 and y=3
HENCE proved
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