If 1/2 and 1 are zeros of 2x^3+x^2-5x+2 find the other zeros
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Hey friend!
Here is your answer:
To find the other zeros of 2x³ + x² - 5x + 2 when ¹/₂ and 1 are the two zeroes of the polynomial
Information:
One degree polynomial ↔ one zero
Two degree polynomial ↔ two zeros
Three degree polynomial ↔ three zeros
Hence, the polynomial has three zeros because it's degree is 3
Let p(x) = 2x³ + x² - 5x + 2
If ¹/₂ is a zero of the polynomial p(x)
x = ¹/₂ ⇒ x - ¹/₂
then,
⇒ x - ¹/₂ is a factor of p(x)
Similarly as 1 is a zero of p(x)
⇒ x - 1 is a factor of p(x)
Now,
(x - ¹/₂)(x - 1) is a factor of p(x)
⇒ x² - ( ¹/₂ + 1)x + ¹/₂ is a factor of p(x)
⇒ x² - ³/₂x + ¹/₂ is a factor of p(x)
On dividing p(x) = 2x³ + x² - 5x + 2 by the factor x² - ³/₂x + ¹/₂,
we must get another factor of p(x) [ of one degree]
[Calculation]
Quotient/Factor = 2x + 4
Hence,
2x + 4 = 0
⇒ 2x = - 4
⇒ x = - 2
∴ The other zero of polynomial 2x³ + x² - 5x + 2 is - 2
I hope it helps you#QualityAnswer
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