Question

If 1/2 and are zeroes of 2x⁴-3x³-3x²+6x-2 find the other zeroes.​

Answer 1

Answer:

0

Step-by-step explanation:

p(x) = 2x^4-3x^3-3x^2+6x-2

p(1/2)= 2(1/2)^4-3(1/2)^3-3(1/2)^2+6(1/2)-2

=2(1/16)-3(1/8)-3(1/4)+6/2-2

=2/16-3/8-3/4+6/2-2

=2-6-12+48-32/16

=50-50/16

=0/16

=0

hope it is correct