Question

if 1.2 g of a metal displaces 1.12 l of hydrogen to ntp, equivalent weight of the metal should be

Answer 1

Answer: Equivalent weight of the metal should be 12 grams.

Explanation: Equivalent weight of metal is defined as the amount of equivalent weight of hydrogen it displaces.

Now, calculate the number of moles of hydrogen at NTP, we use Avogadro's Law:

$\frac{V_1}{n_1}=\frac{V_2}{n_2}$

At NTP conditions:

T = 293 K

P = 1 atm

Volume occupied by 1 mole of gas is 22.4L

Number of moles of gas which occupies 1.12 L can be calculated by using above equation.

$\frac{22.4}{1}=\frac{1.12}{n_2}$

$n_2=0.05moles$

Mass of hydrogen is calculated by using the formula:

$Moles=\frac{\text{Given Mass}}{\text{Molar mass}}$

Mass of hydrogen = 0.05 mol × 2 g/mol = 0.1 g (Molar mass of hydrogen = 2 g/mol)

Now,

0.1 grams of hydrogen is displaced by 1.2 grams of metal

So, 1 gram of hydrogen will be displaced by = $\frac{1.2g}{0.1g}\times 1=12g$ (Equivalent mass of hydrogen = 1 g)

Therefore, the equivalent weight of metal is 12 g.

Answer 2

Answer:

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