If -1+2+iotabeta,beta belongs to R is a root of equation 2x3+bx2+3x+1=0 then find values of b
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=6+2b+3=0
=9+2b=0
=2b=0-9
=2b=-9
=B=-9/2
=b=-4.5
=9+2b=0
=2b=0-9
=2b=-9
=B=-9/2
=b=-4.5
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