Question

If 1\2 is a root of the equation x square+kx-5/4=0,then the value of k is?

Answer 1

Step-by-step explanation:

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Answer 2

$\bf\huge\underline{Question}$

If $\dfrac{1}{2}$ is root of the equation x² + kx - $\dfrac{5}{4}$= 0, then the value of k is?

$\bf\huge\underline{Answer}$

Since, $\dfrac{1}{2}$ is a root of the quadratic equation x² + kx - $\dfrac{5}{4}$ = 0

Therefore, ($\dfrac{1}{2}$)² + k($\dfrac{1}{2}$) - $\dfrac{5}{4}$ = 0

=> $\dfrac{1}{4}$ + $\dfrac{k}{2}$ - $\dfrac{5}{4}$ = 0

=> $\dfrac{1 + 2k - 5}{4}$ = 0

=> 2k - 4 = 0

=> 2k = 4

=> 4