Math, asked by gangstersahil62, 2 months ago

If 1/2 is a root of the equation x² +
kx-5/4 =0 then find the value of k

Answers

Answered by ajay8949
2

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \boxed{ \sf \red {x =  \frac{1}{2}}  }\\

  \:  \:  \:  \:  \:  \:  \:  \: \sf{p(x) =  {x}^{2}  + kx -  \frac{5}{4} }

 \:  \:  \:  \:  \:  \:   \sf{p( \frac{1}{2} ) =  (  \frac{1}{2} ) {}^{2}  + k( \frac{1}{2} ) -  \frac{5}{4}}

  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \blue {\sf{p( \frac{1}{2} ) = 0}}

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \sf {\frac{1}{4}  +  \frac{k}{2}  -  \frac{5}{4}  = 0}

  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \sf{ \frac{k}{2}  -  \frac{4}{4}  = 0}

   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \sf{ \frac{k}{2}  =  {1} }

  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \boxed{\sf{k =  {2} }}

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \pink {hope \:  it \: helps \: you}

Answered by Shiv00729
0

Answer:

We know that α + β = -b/a

αβ = c/a

Let α = 1/2

Then, (1/2) (β) = -5/4

(β) = -5/2. -eq 1

α + β = -k/1

1/2 + -5/2 = -k (since β = -5/2)

K = 4/2 = 2

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